Re: What are the odds of AA and quads back2back
x = getting dealt AA twice in a row is (1/221)*(1/221)
y = rivering quads twice in a row (1/44)*(1/44)
both these happening = x*y
i know this is a very rough calculation that doesnt take everything into account, but the two main points were AA twice in a row, and "rivered quads"
1 in 94 556 176
boohoo
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