Re: Probability question...
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Looks to me like Jason is right.
He's *NOT* saying P(A beats B and C)=P(A beats B)*P(A beats C).
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Thank you for that clarification. That was all that was confusing me.
And yes, I was pretty sure already that jason was right and that I just wasn't following his argument [img]/images/graemlins/smile.gif[/img].
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