Thread: Probability question...
View Single Post
  #3  
Old 04-30-2005, 11:58 PM
jason1990 jason1990 is offline
Senior Member
  
Join Date: Sep 2004
Posts: 205
Default Re: Probability question...
You could get away with a single integral here, if I'm interpreting the assumptions right:

P(A<B,A<C,A<D)=E[P(A<B,A<C,A<D | A)]=E[f(A)]

f(x)=P(x<B)P(x<C)P(x<D)
Reply With Quote