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Old 05-05-2003, 03:17 PM
pudley4 pudley4 is offline
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Join Date: Oct 2002
Location: Mpls, MN
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Default Re: How do i figure this out?

</font><blockquote><font class="small">In reply to:</font><hr />
percent of flops containing precisely two [img]/forums/images/icons/heart.gif[/img] if you hold two [img]/forums/images/icons/heart.gif[/img] :
(11 * 10 * 39) / (50 * 49 * 48) = 3.64%

FYI, the percent of flops containing AT LEAST two [img]/forums/images/icons/heart.gif[/img] if you hold two [img]/forums/images/icons/heart.gif[/img] (this counts the times you flop a flush)
(11 * 10 * 48) / (50 * 49 * 48) = 4.49%


[/ QUOTE ]

Don't we need to multiply these percentages by 3, since we don't care what order the cards come in?
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