Re: Random Math / Theory Question
Here is an example of how to do this:
Board = KQ52
Your hand = AQ
Our estimate of the probability that he would play his hand the way he actually played if he holds:
55 = 10%
KK = 100%
QQ = 100%
AK = 50%
Everything else: 0%
55 = 3 possible hands * 10% = 30
KK = 3 possible hands * 100% = 300
QQ = 1 possible hand * 100% = 100
AK = 9 possible hands * 50% = 450
There is only one possible QQ hand because you can already see two queens.
There are nine possible AK hands because there are three unseen aces and three unseen kings.
P(55) = 30 / (30+300+100+450) = 30/880
P(KK) = 300 / (30+300+100+450) = 300/880
P(QQ) = 100 / (30+300+100+450) = 100/880
P(AK) = 450 / (30+300+100+450) = 450/880
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