[BruceZ]

[ QUOTE ]
What would be the odds of 2 people both having AA and one winning (the first part being key)?

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Heads up:

P(both AA) = 1/C(52,4) = 270,724-to-1

P(both AA) * P(1 AA winning) =

1/C(52,4) * 4*[C(12,4)*36 + C(12,5)] / C(48,5)

=~ 6,226,674-to-1


10 players:

P(2 AA) = C(10,2)/C(52,4) = 6015-to-1

P(2 AA) * P(1 AA winning) =

C(10,2)/C(52,4) * 4*[C(12,4)*36 + C(12,5)] / C(48,5)

=~ 138,370-to-1