Thread: Craps question
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Old 10-04-2002, 01:03 PM
BruceZ BruceZ is offline
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Default Re: Craps question

I believe my method generalizes to:
sum[i = n to m]t(i)*p^m
t(i) = (1/p - 1)[t(i-1) + t(i-2)]


Sorry, make that:

sum[i = n to m]t(i)*p^i
t(i) = (1/p - 1)[t(i-1) + t(i-2)]
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