Verify my straight draw calc?
If I’m dealt 89, what are the chances I will specifically get an open ended straight draw on the flop?
I calculate it as follows: I can get an OESD 3 ways, with 67, 7T, or TJ and all are equally likely. So the chances of 67 is
C(4,1) * C(4,1) * C(40,1) (the 40 is 52 minus 4 5’s, 4 T’s, my 89 and first two 6,7)
---------------------------
C(50,3)
= 3.26%
So 3* 3.26% = 9.79% in total
Did I do this right?
|