[pzhon]

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What is the Median BEST 2 card starting hand dealt to 9,8,7,6,5,4,3,2,1 players?

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Suppose the hands are represented by independent numbers drawn uniformly from [0,1]. The probability that n hands will all be between 0 and x is x^n. You want the median best, x so that x^n = 1/2; x = 1/nthroot(2). For n=10, that is 0.933, so look at the hands that are in the 93rd percentile of your ranking system.

The problem with this simplification is that the hands are not independent, e.g., hands in the top 0.4% tend to repel each other. Nevertheless, I would guess this approximation is reasonably accurate.