Re: Odds of a pair on the flop
the total number of boards is C(52,5).
as far as figuring out at least a pair, find the number of unpaired boards, which is 52*48*44*40*36/5!, and divide this by C(52,5) to find out the probability of an unpaired board.
this simplifies to 44*40*36/(51*50*49), which is right about 50% of boards being unpaired, meaning roughly 50% will contain at least one pair.
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