Re: AA dealt 4 times in 3 hands
Quick and dirty...
3 consecutive A-A hands by itself: 10793860 to 1.
2 consecutive, full ring A-A vs. A-A hands:
[C(10,2) * 1/C(52,4)]^2 = 36193592 to 1
2 consecutive, full ring A-A vs. A-A hands, followed by one particular guy getting A-A:
[C(10,2) * 1/C(52,4)]^2 * 1/221 = 7998784030 to 1
If you'd like to calculate it as if it were heads up, just take the C(10,2)s out.
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