Re: I had 2 RF yesterday in a 1200 hand span
Odds of having a royal on a given hand:
[4 * C(47,2)]/C(52,7) = 4324/133784560 = .00323%
Odds of having exactly two in 1200 hands:
=BINOMDIST(2,1200,4324/133784560,FALSE) = 0.0722959%
Correct me if I'm wrong, it's been known to happen =).
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