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2 hands in a row, same table...
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12-15-2005, 06:07 AM
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Re: 2 hands in a row, same table...
All you have to do is find the probability of getting KK and square it because the hands are independent. ((4/52)*(3/51))^2= .00002047460125 or 48841 to 1. I think I did the math correctly.