Re: Identical Random Shuffles?
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For heads-up the total number of effectively unique shuffles would be close to (in case I missed something):
P(52,4)/4*C(48,3)*47*46/4!
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oops, try this instead:
C(52,2)*C(50,2)*C(48,3)*45*44/4!
=2 317 817 502 000
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