Re: Two Identical flops
while your answer is correct, its pretty deluded
the (more easliy understandable) answer is : (1/50)(1/51)(1/52) = 1/132600 = .0008%
this is the odds that 2 predetermined flops will be identical
the odds that after seeing a flop that one of your other 3 tables will contain the same flop is .0008%*3 or .0024%
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