[Louie Landale]

Heads up if you have hand 50% then you are even money to have the best hand. That is, the median "best" hand for one player is hand 50%.

Against 2 players your hand h% is "best" when it beats the first player AND the 2nd player. Chances it beats the first player is h. Chances it beats both is h**2. .5 = h**2. h = 2ndRoot of .5; =70.1%. So if you have hand 70.1% you are 50:50 to have the best hand against 2 random hands.

** Average best hand for n opponents is nthRoot of .5. **

- Louie

Be advised that the actual rank of hands changes somewhat as N changes: trouble hands go down in relative value as N increases (A2 ranks higher heads-up than at a full table); suited hands go up.

This is interesting if you are adopting a starting strategy that says play if you are 50:50 to have the best hand or better.