Re: My solution
Ok, we've seen that B's strategy of calling at above 1/2 and raising at over 3/4 is not optimal. But what is A's best counter to this strategy?
On the one hand, if A ALWAYS calls the raise when he has a hand 3/4 and above, it doesn't change B's EV at all over and above the non-raising scenario: A folds to the raise below 3/4 and loses only the $1 he would have lost anyway. But if both players have hands above 3/4, it's a wash with 0 EV for B. So, the value of the game is just .25 for B, as it is in the non-raising game.
This just seems a little strange to me, because A is only getting 3:1 pot odds on the call. So, it would in a sense seem that if he had the hand .75000000001, he doesn't have the odds to call. B will win his additional dollar 99.99999999% of the time?!
So, if A calls the raise on on the top 2/3 of the hands that B will raise (calls raise at 5/6), what happens? I get that he actually REDUCES B's EV from the original scenario by 1/48 to 1/4-1/48 = 11/48.
Is this correct?
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