Re: A9- How often am I Behind?
They can have 22-88,TT-KK 6 different ways apiece, for a total of 66 hands. They can have 99 or AA 3 different ways for a total of 6 hands. They can have AT-AK 3*16=48 different ways (3 Aces, 16 T,J,Q,K). So there are a grand total of 120 hands that beat you. There are 1326 total starting hands, so the odds of one oppenent beating you is
120/1326=9.6%
The odds of one of two opponents beating you is approximately 1-(1-.096)^2=17.2%. To get an extact answer you would have to use inclusing/exclusion which I don't feel like doing.
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