[KJL]

The odds that four opponent are dealt four different pocket pairs is:
C(4,2)/C(52,2)*C(4,2)/C(50,2)*C(4,2)/C(48,2)*C(4,2)/C(46,2)=~.00000000066
The odds that three of those pocket pairs turn into sets and one becomes quads is:
C(2,1)*C(2,1)*C(2,1)*C(2,2)/C(44,5)=~.0000008
The odds of this all happening is the product of the two probabilties, which is: ~.0000000000000005

These odds assume that order dosen't matter, if it did the odds would be even smaller.