[AleoMagus]

Against nine random hands, I think you certainly make more by getting them all in. You want as many random callers as possible.

The interesting thing though is that poker is not played against random players. Players who will push and players who will call pushes can usually be put on a specific range of hands. Even the crazy nuts have limits.

What this means then is that you are more likely up against other pairs and you are more likely to have your other aces in other people's hands. In some extreme cases, you can even be a huge underdog to win the hand.

I read about one interesting scenario where AA was about 50-1 AGAINST winning a ten player preflop all-in scenario. I forget what the hands were exactly, but experimenting for a minute on my own I came up with a few scenarios where AA was about 20-1 against winning the hand.

These scenarios mostly involved situations where two ther opponents had your extra aces (AK and AQ for example) and where there were a lot of other pocket pairs out

These are just the sort of hands that might theoretically call in a ten player all-in scenario.

In fact, I will suggest here that if nine players go all-in ahead of you, you would rather be holding a hand like 88 than you would AA for this reason. Your other two eights are still probably in the deck.

So, while this sort of thing will never happen anyways, I think I'd sooner have three opponents with pocket aces than ten.

Perhaps someone can find that 50-1 against preflop aces scenario I was thinking about. I'd be interested to see it again.

Regards
Brad S