Re: How many royals have you had to date?
If I have this right, the odds of making a "full-full-house" are:
52/52 * 51/51 * 6/50 * 5/49 * 4/48 * 3/47 * 2/46 = 0.0000028318450414
or 1 in 353126.67
Again, assuming my probability reasoning is right. I'm not sure this is right since it doesn't describe the possibility of pocket pairs.
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