Simply Risk of Ruin Question
Suppose I like to play -EV games and go to a casino to play some Roulette (double zero).
If I take $50 and decide to stay until I double up or go broke what are the odds that I walk away with $100 assuming I play the following ways:
a) always bet $10 on black
b) always bet $1 on black
c) always bet $10 on the first row of 12
d) always bet $1 on 00
Even if you don't want to do the math, how would you go about finding these results?
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