Re: AA vs AA with one winning
[ QUOTE ]
What would be the odds of 2 people both having AA and one winning (the first part being key)?
[/ QUOTE ]
Heads up:
P(both AA) = 1/C(52,4) = 270,724-to-1
P(both AA) * P(1 AA winning) =
1/C(52,4) * 4*[C(12,4)*36 + C(12,5)] / C(48,5)
=~ 6,226,674-to-1
10 players:
P(2 AA) = C(10,2)/C(52,4) = 6015-to-1
P(2 AA) * P(1 AA winning) =
C(10,2)/C(52,4) * 4*[C(12,4)*36 + C(12,5)] / C(48,5)
=~ 138,370-to-1
|