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Old 11-07-2005, 05:51 PM
BruceZ BruceZ is offline
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Join Date: Sep 2002
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Default Re: Pinochle Question

[ QUOTE ]
One team should get all the Aces around 20.3% of the time. The easiest way to figure this out to is to calculate the odds of one team being dealt no Aces:

(40/48)*(39/47)*(38/46)*(37/45)*(36/44)*(35/43)*(34/42)*(33/41)

[/ QUOTE ]

That expression is the proabability of no aces in 8 cards. We want the probability that one team gets no aces in 24 cards times 2, since it can happen to either team.

2*C(40,24)/C(48,24) =~ 0.40% or 1 in 256.5.
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