Re: Question on counting outs
Against a set we have about .5 outs, against A8 we have 3 outs, against A3 we have 6 outs, and against A2 we have 9 outs. Assuming he's only making this move with those hands (pretty reasonable), and there are 9 sets he can have and 2 of each suited aces, I'd give us:
.5(9) + 3(2) + 6(2) + 9(2) = 40.5 / 15 different hands = 2.7 outs sounds pretty reasonable.
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