Re: Can one overcome a -EV game?
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Without involving infinities it will still always be -EV
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Well the point is not to change a negative EV to a positive EV. The point is that involving infinites on the side of the -EV player one can take all of the Casino's finite bankroll. I do not know the math or the xact amount necessary but I would bet that one could come up with two reasonable finite numbers (one for the Casino and one for the opponents) would yield a > %99.999999 probability that the -EV player would win all of the Casino's money using a double up system
Vince
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