Re: Classic Type Game Theory Problem
Let's replace a number > 0.50 with 1 and a number < 0.50 with 0. The reason to do this is that if you redraw with a number higher than 0.50, it is more likely that you will make it worse.
Under this assumption and with "optimal" play for both sides I got an EV of 0!
If player A has 1 he stands (EV: +12.5%) and if he has 0 he redraws (EV: -12.5%). That play has a better expectation than trying to stand/bluff with 0 (overall EV: -25%).
Player B always stands with 1 and always redraws with 0.
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