Re: interesting problem
If you are choosing without replacement, then the lowest winning number possible is 2/3 of the lowest mean possible, which is 9. So you would pick 6. Knowing that, you would not want to pick 0 - 5 which then increases the mean. So now, you're going the other way and assume 6 - 26 will be chosen. You could iterate the whole process again ultimately ending up choosing 80 - 100 but that can't be right so you start down again. So I'll take a stab and say 50 is the best guess.
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