[sexdrugsmoney]

</font><blockquote><font class="small">En respuesta a:</font><hr />
Roland, I hope you got some rest.

What I'm trying to wrap my math challenged head around is this:

Hero has the pot odds to call a bet on sixth. Pot would be offering 6.25:1, while Hero is a 3:2 underdog. Hero should not want to bet himself now that his EV (0.404) is less than 50% in this HU hand. Each bet that he now makes costs him money, e.g.

Pot = 5.25 BB and Hero wins the hand 2 times out of 5.

Looking at Sixth street in a vacuum.

Sixth street (no bets):

3 losses * 0 BB (additional investment) = 0 BB.
2 wins * 5.25BB pot = 10.5 BB. (10.5 BB - 0 BB = 10.5 BB)


Sixth street (one bet):

3 losses * 1 BB = 3 BB.
2 wins * 6.25 BB = 12.5 BB. (12.5 BB - 3 BB = 9.5 BB)


Sixth street (2 bets):

3 losses * 2 BB = 6 BB
2 wins * 7.25 BB = 14.5 BB (14.5 BB - 6 BB = 8.5 BB)

So while you still make money, you make less for each additional bet. SDM, does this make any more sense? I'm not a math person either.

Ray, I think this is what you were saying but just a different way of showing it.

[/ QUOTE ]

I wish it did greenage but I think I'll have to study it on my own further, and possibly take a primer in maths first.

Cheers though.