[BruceZ]

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Forgive the newbie question (it's been a long time since I took statistics) but can you break down what each part of the formula is? Is it 2 players, 2 outs (each), 44 cards that don't help, and the # combinations of 3 cards out of 48 remaining?

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2 cards that make one set, times 2 cards that make the other set, times 44 cards for the 3rd card, divided by # combinations of 3 cards out of 48 remaining.

Or just use fractions:

2/48 * 2/47 * 44/46 * 6.

We multiply by 6 since the cards can come in any of 6 orders. Note that this is the same as 2*2*44/C(48,3) since C(48,3) = 48*47*46/6.