Re: Searched...no luck...
The probability of getting a pair and only a pair is
=2*3*(44c2)/(50c3) = 28.96%
Assume you have AK there are three aces left and three kings. There are 44 other cards. Let say you want the probablity of hitting a pair of aces and only a pair that would be 3*(44c2)/(50c3) but the probability of hitting either ace or a king would be twice this.
Cobra
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