Re: Some basic questions on winrate probability
I am too lazy to compute your intervals (I actuallly would have to look up how to do it, because I forgot). Anyhow, here is a basic summary:
n = 2000 (sets of 100 hands)
m = 1.6 (mean big bets won per 100 hands)
s = 15.6 (standard devitions in big bets per 100 hands)
95% CI = m +/- 1.96 (s/sqrt(n))
So 95% of the time your next sample set of hands will be between [0.91 - 2.28] big blinds per hour.
You can easily infer that the chance you will be >3 or <0.5 will be less than 2% each.
All of this is of course assuming that you are playing the same, your opponents are playing the same, and any and all other underlying conditions have not changed.
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