Re: K5s, posting in the CO, flop decision
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Pax and I are working on trying to figure out the exact probability here, but it may be a while. As a hopeless math geek this interests me for some sadistic reason; I'll come back with results.
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I thought we were just doing this for fun [img]/images/graemlins/frown.gif[/img]
What I came up with : There are 55 remaining combinations of 2 clubs, and 1176 possible preflop hands. The chance of an individual not having 2 clubs is 1-[55/1176] = 95.32%, and the chance of all 6 Villains not having 2 clubs is 95.32%^6.
By my math, there is a 75.007% chance that no one is holding two clubs here.
Even if absolutely no one else had a club, the chance of the 7th person getting two clubs is still only 9.24% [(11/35)*(10/34)].
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