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Old 08-18-2005, 12:14 AM
BruceZ BruceZ is offline
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Join Date: Sep 2002
Posts: 1,636
Default Re: A ridiculous SAT question...

[ QUOTE ]
I have no idea why I cannot solve this problem. Its from the SAT; any help would be appreciated. (the first part is just the square root of the quantity (x squared plus t squared), I just dont know how to type that.)

(x^2+t^2)^1/2 = 2t-x

If x and t are positive numbers that satisfy the equation above, what is the value of x/t?

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(x, t, 2t-x) must be a pythagorean triple, meaning that x^2 + y^2 = (2t-x)^2. The first triple (3,4,5) fits the bill, so x = 3, t = 4, and x/t = 3/4. The proof of uniqueness is that this is a SAT question. [img]/images/graemlins/smile.gif[/img]

You can write square root as sqrt(x).
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