[ninjia3x]

Thanks for the reply,

My friend asked me to approximate the odds, and i gave around 2:1 to 3:1.

I started by assuming the odds, then finding if it will yield a positive result for player A.

what i did was Player won't play a hand unless he is a 2:1 favourite. (if you choose to go all in) That leaves pocket pairs of your highest card and up, plus hands that has one your cards with a higher kicker.

with the intial pot at 3. my EV was 3*(probability he doesn't have the right odds) - (probablity he does have the right odds)*(6/7)*(1/3)

when he calls i'm assuming his odds of winning are 6:1 on avg. the 1/3 is the odds he gave me.

Does anyone think this makes sense?