[BruceZ]

llamaoo7:

I originally made these edits to your post by accident, but I put your original post back. That's why yours says it is edited by me.

-Bruce


[ QUOTE ]
For JJx, there are 3 ways of getting the two remaining jacks from the last 3. This works out to 3 ways and for each of these ways, you have 48 additional cards that can come, so you have 144 ways of this scenario.

[/ QUOTE ]

This counts JJJ 3 times, so the total should be 142


[ QUOTE ]
For 22x, the calculation is the same as above, so there are 144 ways of this occuring.

[/ QUOTE ]

This counts 222 3 times, so the total should be 142.


[ QUOTE ]
For J2x, you have to consider the chances of getting that J and the 2 AND the last card can't be a J or a 2 or you will be overcounting because JJx and 22x has these situations covered. So to get a J and a 2, you have 3 ways of picking a J and 3 ways of picking a 2. Then out of the remaining cards, there are only 46 that will give you two pair and not a boat which has already been counted. so 3*3*46 gives you 276.

[/ QUOTE ]

3*3*46 does not equal 276, and anyway it should be 3*3*44 = 396.