Re: I had the same hand dealt to me twice in a row...
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Say I'd played 350k hands and the odds were 7m:1
You could say that the chances of this happening to me were about 5%.
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To figure out the odds of something like this, the easier way is to calculate the probability of the given even *not* happening, and then subtract that from 1. So the probability of your getting the same time twice in a row is 1/1326 for any given two hands. The probability of getting the same hand twice in a row in three hands would be 1 - (1325/1326)^2. The probability of 1 - (1325/1326)^924 is 0.5, so you could expect to get the same hand twice in a row about half the time in a session of 924 hands. I think this is correct. Not 100% sure, but seems right.
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Makes sense.
This sounds like how they calculate the prop bet "no two people have the same birthday in this room".
They don't work out scenarios like 3 people havinvg the same birthday...
Thanks.
It's been a long time since I've tried to figure out any of this stuff. [img]/images/graemlins/smile.gif[/img]
--Dave.
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