Re: Sklansky -Fermat Conjectures
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Conjecture Two: If there are in fact q's for which the conjecture holds, some will be formally unprovable.
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That doesn't look like a conjecture. That looks like a guess. I'd bet $1k against it, even money.
My point is that I think there are qs for which the conjecture holds for no logical "reason" other than "sparseness".
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It might be much easier to show that such q's exist than to actually find them.
PairTheBoard
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