[MikeL05]

[ QUOTE ]
You may think it, but that doesn't make it so.

Suppose you have 2 cards to come. If the dealer burns 3 cards instead of 1, do your odds of winning change at all? Of course not.

So your odds of winning the first run are equal to the odds of winning the second run. Therefore, EV is the same.

[/ QUOTE ]

I'm sorry, I'm new here, but this makes absolutely no sense.

First, your example of burning 3 cards is both (a) obvious, and (b) irrelevant. In that case, the burned cards are unknown. In my case, we KNOW that they are, for example, two diamonds.

As far as my odds of winning the first run being equal to my odds of winning the second run... this is also ridiculous. If I have AA and you have KK, and we're all in after a flop of 4-8-T rainbow and decide to run it twice... KK has perhaps a 10% chance of winning. Say the first run is a turn of K and a river of K. Now for the second run, KK has a 0% chance of winning.