Re: Poker puzzle challenge - Fundamental theorem
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as far as i can see this is one:
you have Q[img]/images/graemlins/heart.gif[/img]Q[img]/images/graemlins/spade.gif[/img], and the board after the turn is:
Q[img]/images/graemlins/club.gif[/img]9[img]/images/graemlins/club.gif[/img]6[img]/images/graemlins/diamond.gif[/img]3[img]/images/graemlins/diamond.gif[/img]
you are up against 9 opponents who hold:
99
66
33
4[img]/images/graemlins/club.gif[/img]5[img]/images/graemlins/club.gif[/img]
7[img]/images/graemlins/diamond.gif[/img]8[img]/images/graemlins/diamond.gif[/img]
J[img]/images/graemlins/spade.gif[/img]T
A[img]/images/graemlins/heart.gif[/img]A[img]/images/graemlins/spade.gif[/img]
57
QJ[img]/images/graemlins/heart.gif[/img]
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Nice example! The only problem that I see is that a few of the hands (8 [img]/images/graemlins/diamond.gif[/img]7 [img]/images/graemlins/diamond.gif[/img], 4 [img]/images/graemlins/club.gif[/img]5 [img]/images/graemlins/club.gif[/img]) have about 30% equity against your hand, and thus depending on the size of the bet and the pot, it would not be a "mistake" to call. In limit with nine callers going to the turn, the pot would be quite large and they definitely have the correct odds to call. I guess it could work in no limit if you can bet enough to price out those hands, and also negate their implied odds.
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