Re: Probability of making a full house
Thank you very much for your help.
I corrected the calculation ...
Total of combinations: C(47,3) = 16'215
9 ranks with 4 cards left:
9 * C(4,3) = 9 * 4 = 36
9 * C(4,2) * 2[aces] = 9 * 6 * 2 = 108
3 ranks with 3 cards left:
3 * C(3,3) = 3 * 1 = 3
3 * C(3,2) = 3 * 3 * 2[aces] = 18
36+108+3+18 = 165 combinations of a total of 16'215 combinations make the full house.
16'215/165 = 98.3
= 97.3-to-1 or about 1.02%
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