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Old 03-18-2005, 07:46 PM
EasilyFound EasilyFound is offline
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Join Date: Mar 2005
Posts: 330
Default Re: Specific Hand Probability

I meant this: the probability that there will be no ace in any of the 5 pockets.

The probability that you will not have an Ace in your pocket is 85%. And the probability that none of five players will have and Ace is roughly 41%.

I wanted to know whether there was a quick formula to follow to get from the first figure to the second.

But after reading the replies here, I now understand that this stat thing is way too complicated for my head at my age.

I just need someone to break it down into a chart, like the one Brunson has in his book for the probability on the absence of Aces.

Thanks to all who took the time to reply. Will try to digest it all and see if I can grasp it.
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