Re: Specific Hand Probability
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Five handed, probability nobody will have an Ace is 48.6 %.
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I believe you are misstating the above assuming you mean the probability that there will be no ace in any of the 5 pockets. The probability that no one will have an ace in 5 pockets is:
C(48,2)/C(52,2) * C(46,2)/C(50,2) * C(44,2)/C(48,2) * C(42,2)/C(46,2) * C(40,2)/C(44,2)
= (1128 * 1035 * 946 * 861 * 780) / (1326 * 1225 * 1128 * 1035 * 946)
= 41.34%
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