Re: Do You See why?
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8 8: Any combination with the last 8, except for the one with the last Ace => 43 combinations.
2 3: Any combination with two diamonds (34) and all combinations with a 4 and a 5 (9) => 43 combinations.
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D.H., your final result is correct, however, your subtotals are wrong.
For the 2 3 hand, there are 36 combinations of diamonds but must eliminate the 8 which include the 6 as it makes a full house for opponent. So flush combinations are 28. There are 16 straight combinations, but we have already counted the the diamond one (4d5d), so total is 15. The 28 + 15 gives us the 43 combinations.
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