Re: Hand Probability Expanded - Is My Thinking Correct
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I suppose you'd have to calculate how often zero, one, two, three, etc. premiums would have been dealt over two orbits, and then take the weighted average of that. I don't doubt it's close to one, but I'd be willing to bet it's not exactly that.
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LinusKS
Thanks for the reply. I'm not a math whiz but logically I was thinking that the hand probability for an individual could be spread over a 10 table game (10 person to keep the math easy for my question). I don't know if my logic is flawed. I think the weighted average angle you delved into would provide some clarity to the question. I'm trying to think this through but am still stuck and not sure if this logic is correct.
Greg H.
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