[pzhon]

[ QUOTE ]
if the bonus ball is 25 then add up the remaining balls. there is an equal # of even and odd balls now. if the number is even Player 1 wins, if it's odd Player 2 wins.

[/ QUOTE ]
Sorry, that doesn't work. Among the 48C6 = 12,271,512 ways the bonus ball could be 25, only (24C6+(24C4)(24C2)+(24C2)(24C4)+24C6)= 6,134,744 = 49.9918% have an even sum, while 6,136,768 = 50.0082% have an odd sum.

You shouldn't expect a method to work if it would apply to an impossible case such as if the numbers were 1-47, so that the number of tickets would be odd.