Re: A pair in the flop
Thank you both for the answers. I am having some trouble understanding parts of the answer. I hope you don't mind giving me a little math lesson.
So it should be 13*6*48/(52 choose 3) = .1694
The "c" or choose is confusing to me. I understand +-/* but not choose. Can you explain the process?
Also, since the percentage is .1694 that translates to about a 5.9/1 dog. Meaning one in 6 flops will probably contain a pair. If that is true, I have indeed learned something.
Thanks,
Jack
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