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-   -   Interesting Puzzle (http://archives2.twoplustwo.com/showthread.php?t=298745)

ihardlyknowher 07-23-2005 03:47 AM

Interesting Puzzle
 
Forgive me if this has been posted or if it is trivially easy. I found it interesting.

Your are given 12 marbles, identical in appearance. Exactly one marble has a mass either slightly more OR slightly less than the other 11 (the difference is so minimal no human could possibly detect it without the use of scientific equipment). You are given a balance and allowed to use it exactly 3 times. You must determine which marble has a slightly different mass and whether it has more or less mass than the other 11. How do you do it?

Dov 07-23-2005 04:34 AM

Re: Interesting Puzzle
 
This would be trivial if you knew whether it was more or less massive. Isolating it would then go as follows (assuming more massive):

1. Place 6 on each side and discard the lighter ones
2. Place 3 of the remaining 6 on each side and discard the lighter ones
3. Place 1 of the remaining 3 on each side:
A. If one side is heavier than the other, then that is the target.
B. If they both balance, then the target is the one not on the balance.

I still have to think more about modifying this procedure to answer the original problem.

Dov 07-23-2005 04:38 AM

Re: Interesting Puzzle
 
New approach!

Roll them all down an inclined plane and the one that arrives out of phase with the others is the different one.

If it arrives earlier, then it is more massive.
If it arrives later, then it is less massive.

Rent your 3 balance trials to recoup the cost of the marbles. [img]/images/graemlins/cool.gif[/img]

Quaalude 07-23-2005 04:46 AM

Re: Interesting Puzzle
 
[ QUOTE ]
New approach!

Roll them all down an inclined plane and the one that arrives out of phase with the others is the different one.

If it arrives earlier, then it is more massive.
If it arrives later, then it is less massive.

Rent your 3 balance trials to recoup the cost of the marbles. [img]/images/graemlins/cool.gif[/img]

[/ QUOTE ]

Nope, won't work I'm afraid. Gravity will pull all objects down at the same speed (ignoring air resistance, which will have about as close to zero effect as you can get in this case). Remember that funny little experiment that Galileo did?

lucktard 07-23-2005 05:05 AM

Re: Interesting Puzzle
 
<font color="white"> Divide the marbles into 3 groups of four and compare the weight of two of the groups. If they weigh the same then one of the 4 unweighed marbles is the "bad" one, this is trivial to solve.

Otherwise you have 8 marbles that could possibly be bad (4 that could be light and 4 that could be heavy) and 4 marbles that you know are good. Call the 4 on the light side 1-4 and the four and the heavy side 5-8. Now compare the weight of marbles 1, 2, and 5 with the weight of marbles 3, 4, and 6.

If the scale now balances, either 7 or 8 is heavy, use the last weighing to determine which.

If side 1,2,5 is now heavy then either 3 or 4 is light or 5 is heavy. Measure 5 and 3 against two of the known good marbles. If side 5,3 is heavy, then 5 is heavy, if it's light then 3 is light and if it balances then 4 is light.

If side 3,4,6 was heavy in the second measurement then 1 or 2 is light or 6 is heavy. Weight 3 and 4 against two good marbles to find out which.
</font>

Dov 07-23-2005 05:14 AM

Re: Interesting Puzzle
 
[ QUOTE ]
Nope, won't work I'm afraid. Gravity will pull all objects down at the same speed (ignoring air resistance, which will have about as close to zero effect as you can get in this case). Remember that funny little experiment that Galileo did?

[/ QUOTE ]

I know, it was a joke. Hence the smiley.

But thanks anyway.

I hope everyone's having a good weekend.

BruceZ 07-23-2005 07:07 AM

More difficult version
 
[ QUOTE ]
Forgive me if this has been posted or if it is trivially easy. I found it interesting.

Your are given 12 marbles, identical in appearance. Exactly one marble has a mass either slightly more OR slightly less than the other 11 (the difference is so minimal no human could possibly detect it without the use of scientific equipment). You are given a balance and allowed to use it exactly 3 times. You must determine which marble has a slightly different mass and whether it has more or less mass than the other 11. How do you do it?

[/ QUOTE ]

I saw a more difficult version of this problem where you are not allowed to base your measurements on the result of previous measurements. Everything else is the same.

ihardlyknowher 07-23-2005 01:11 PM

Re: Interesting Puzzle
 
Had you seen this before?

NutzyClutz 07-23-2005 06:33 PM

Re: Interesting Puzzle
 
Get an aquarium. Put the marbles in. Fill with water. Add salt slowly. If the marble is light, it will be only marble to rise. If marble is heavy. It will be only marble not to rise.

Line up the marbles in a wind tunnel slowly increase wind....

Put each marble, in US Golf Assoc. testing machine... The marble the is driven the "odd" distance ...

Fire pairs of marble at each other headon, the marble pair that doesnt rebound equally has the "odd marble". Take one of these marbles, and fire it with one of the other 10 marbles, if it rebounds equally, the marble you didnt select is the "odd marble". Otherwise, the marble you selected is the "odd marble"

Sandblast each marble. Measure the amount of sand used for each one. The odd amount of sand is the "odd marble"


Attach 1 marble to each side of a precision dice. Roll die 10,000,000 times to determine dice bias. The number that came up most, the odd marble is either attached to that side, or on the opposite side. Take one of these marbles, and attach it to coin. Take one of the other 10 marbles, and attach it to other side of coin. Flip 10,000,000. If the coin is biased, then the marble you selected is the "odd marble", if not biased. the marble you did not select is the "odd marble"

Hook up the marbles as follows
web page
Coax the person who knows the answer into state of hypnosis...

PairTheBoard 07-24-2005 01:57 AM

Re: Interesting Puzzle
 
I have not looked at the comments yet and am still thinking about this one.

PairTheBoard


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