odds of specific hands coming on board.
what are the odds of:
exactly one flush and exactly one full house being on the board in 30 hands? just wondering how the math works with this. to simplify, (and i hope this is right), we can assume that a flush comes on board 1/509 times, and a FH 1/694 times. then what? |
Re: odds of specific hands coming on board.
[ QUOTE ]
what are the odds of: exactly one flush and exactly one full house being on the board in 30 hands? just wondering how the math works with this. to simplify, (and i hope this is right), we can assume that a flush comes on board 1/509 times, and a FH 1/694 times. then what? [/ QUOTE ] Actually the flush is 13*C(13,5)/C(52,5) = 1/505. The FH is 1/694 as you said. The odds of exactly one of each in 30 hands is: C(30,2)*2*(1/505)*(1/694)*(1 - 1/505 - 1/694)^28 = 442-to-1 |
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