please solve an equation for me
 

equation:

10 * [sqrt(n)/sqrt(k)] * [1+log(b+0.25)]


n = 29
b = 40
and
k=1 and k=2

i need it solved for both k=1 and 2 pls.

this is to verify a technical issue and i don't feel like struggling with this when it would take many of you 10 seconds

tyvm

Re: please solve an equation for me
 

The answer is "next Thursday"

Seriously, log-base-what? LN?

Re: please solve an equation for me
 

[ QUOTE ]
The answer is "next Thursday"

Seriously, log-base-what? LN?

[/ QUOTE ]

WTF do i know???

does this help doggy?

The points formula used to determine the total points awarded to a player in a multi-table tournament (in the top 15% finishers) for any given tournament is:

Points = 10 * [sqrt(n)/sqrt(k)] * [1+log(b+0.25)]

Where:
n is the number of entrants
k is the place of finish (k=1 for the first-place finisher, and so on)
b is the buy-in amount in dollars (excluding administrative fee). For freerolls the buy-in is $0

Example 1: A player takes third place in a $20 tournament with a field of 150 players. Here:

n = 150, k=3, b=20

The total points awarded to this player are:

= 10 * [sqrt(n)/sqrt(k)] * [1+log(b+0.25)]
= 10 * [sqrt(150)/sqrt(3)] * [1+log(20+0.25)]
= 10 * sqrt(50) * (1+1.31)
= 10 * 7.071 * 2.31
= 163.09 (rounded up)

Re: please solve an equation for me
 

k=1 --> 140.271
k=2 --> 99.187

Re: please solve an equation for me
 

technically you posted an expression, not an equation - but since you were right it would take like 10 seconds... use our friend google to evaluate the expression:
google evaluates the expression for us

to get result for k = 1:
10 * ((29^.5) / 1) * (1 + log(40.25)) = 140.270936

k =2 gives you this:
10 * ((29^.5) / (2^.5)) * (1 + log(40.25)) = 99.1865299

HTH,
ninjageek

Re: please solve an equation for me
 

That's what I got.

Re: please solve an equation for me
 

tyvm

there was a glitch and this dude's name was stuck at top (he went out first 10 minutes) and my tourney report never came.

for the wsop contest i need to know
1. whether it was worth bringing to the attention of support
(which it is cuz the points double)
and
2. i want to check tomorrow and see what was actually awarded before i bother them

http://www.picturehost.co.uk/free.one/shell.JPG



edit: and as you can see on left, it says i finished 2nd

Re: please solve an equation for me
 

[ QUOTE ]
The answer is "next Thursday"

Seriously, log-base-what? LN?

[/ QUOTE ]

If it was the "natural log" it would have been Ln in the equation, "LOG" nomenclature is Log base 10

Re: please solve an equation for me
 

[ QUOTE ]


If it was the "natural log" it would have been Ln in the equation, "LOG" nomenclature is Log base 10

[/ QUOTE ]

see, it is shiit like this that makes my

http://users.telenet.be/eforum/emoti...t/sterb207.gif

Re: please solve an equation for me
 

TLB point calculator